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Question

If A=⎡⎢⎣0121233a1⎤⎥⎦;A−1=⎡⎢⎣1/2−1/21/2−43C5/2−3/21/2⎤⎥⎦ then values of a and c

A
1,1
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B
1,2
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C
1,1
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D
None
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Solution

The correct option is C 1,1
A=0121233a1 A1=1/21/21/243C5/23/21/2
AA1=I
0121233a1 1/21/21/243c5/23/21/2 =100010001
10c+1012c+244a3aa/32+ac = A=100010001
c+1=0
c=1
44a=0
a=1

1069864_1166145_ans_170dbdde03e0484c9034b6d3c71913b5.jpg

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