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Question

If $A= [0124] B= [−1122] $,

and C=[1010], then 2A+3B−C=

A
[45914]
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B
[43910]
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C
[45914]
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D
[45149]
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Solution

The correct option is A [45914]
2A+3B-C=0248+33661010=45914

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