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Question

If A=[023−4], kA=[03a2b24],then the values of k, a, b respectively are ______ .


A

-6, -12, -16

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B

-6, 4, -9

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C

-6, -4, -9

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D

-6, 12, 18

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Solution

The correct option is C

-6, -4, -9


A=[0234], kA=[03a2b24]

-4 = 24k

k = 244 = -6

3ak=2

3a6=2

a = -4

2bk=3

2b6=3

b = -9


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