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Question

If A=[0α00] and (A+I)5050A=[abcd], then the value of a+b+c+d is

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Solution

We have, A2=[0α00][0α00]
=[0000]=O
Ak=O, k2
Thus,
(A+I)2=A2+I2+AI+IA=I+2A
(A+I)3=(A+I)2(A+I)=(I+2A)(A+I)=I+3A(A+I)50=I+50A(A+I)5050A=I+50A50A=I[1001]=[abcd]a=1,b=0,c=0,d=1a+b+c+d=2

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