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Question

If A=0x16x5709x is singular, then the possible values of x are

A
0,±1
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B
0,±12
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C
0,±5
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D
0,±4
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Solution

The correct option is D 0,±12
Singularmeans|A|=00x16x5709x=00(5163)x(x2)+16(9x)=0x3+144x=0x3144x=0x(x2144)=0x=0x2144=0x2=144x=±12x=0,±12

Hence, this is the answer.

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