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Question

If A=101023121 and B=123115247 then, find a matrix X such that XA=B.

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Solution

XA=B

XAA1=BA1

X=BA1

A1=Ad(j)(A)|A|

|A|=1[26]+0+1[2]

=42=6

Adj=+C11C21C31C12C22C32C13C23C33=422303222

X=123115247422303222

X=4+662+0626+64+3102+01023+103+1214414412+14

X=442118510102

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