If A- 1 -1 1- 0 2 -3- 2 1 0 -B-adj A and C-5A- then - C - - adj B - is equal to

The correct option is D 1 Since, A=[ 1 amp; 1 amp; 1; 0 amp; 2 amp; 3; 2 amp; 1 amp; 0 ],B=(adj A) B=adj(A)=[ 3 ...

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Multiplication of Matrices

If A=[ 1 -1...

Question

If $A = ⎡ ⎢ ⎣ \begin{matrix} 1 & - 1 & 1 0 & 2 & - 3 2 & 1 & 0 \end{matrix} ⎤ ⎥ ⎦, B = (a d j A)$ and $C = 5 A$ , then $\frac{| C |}{| a d j B |}$ is equal to

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A = ⎡ ⎢ ⎣ \begin{matrix} 1 & - 1 & 1 0 & 2 & - 3 2 & 1 & 0 \end{matrix} ⎤ ⎥ ⎦, B = (a d j A)

C = 5 A

\frac{| a d j B |}{| C |}

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & - 1 & 1 0 & 2 & - 3 2 & 1 & 0 \end{matrix} ⎤ ⎥ ⎦

B = (a d j A)

C = 5 A

\frac{| a d j B |}{| C |} =

A = ∣ ∣ ∣ ∣ \begin{matrix} 1 & - 1 & 1 0 & 2 & - 3 2 & 1 & 0 \end{matrix} ∣ ∣ ∣ ∣

B = (a d j A)

C = 5 A

\frac{| a d j B |}{| C |}

A = ⎡ ⎢ ⎣ \begin{matrix} 3 & - 3 & 4 2 & - 3 & 4 0 & - 1 & 1 \end{matrix} ⎤ ⎥ ⎦, B = (a d j A)

C = 5 A

\frac{| C |}{| a d j B |}

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 1 & 2 1 & 3 & 4 1 & - 1 & 3 \end{matrix} ⎤ ⎥ ⎦, B = adj A

C = 3 A

\frac{| a d j B |}{| C |}

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