If A - - 1 1 1- 1 2 3- 1 3 4 - B - - 7- 16- 22 - X - - x- y- z - and AX - B then z is equal to

The correct option is B 3 AX=B #160; 1 amp;1 #160; amp;1 #160; 1 amp; 2 amp; 3 1 amp;3 #160; amp;4 #160; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Consistency of Linear System of Equations

If A = [ 1 ...

Question

If $A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 1 & 1 1 & 2 & 3 1 & 3 & 4 \end{matrix} ⎤ ⎥ ⎦, B = ⎡ ⎢ ⎣ \begin{matrix} 71622 \end{matrix} ⎤ ⎥ ⎦, X = ⎡ ⎢ ⎣ \begin{matrix} x y z \end{matrix} ⎤ ⎥ ⎦$ and $A X = B$ then $z$ is equal to

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

\frac{y - z}{a (b - c)} = \frac{z - x}{b (c - a)} = \frac{x - y}{c (a - b)}

\frac{x}{3 x - y - z} = \frac{y}{3 y - z - x} = \frac{z}{3 z - x - y}

x + y + z \neq 0

\frac{a x + b y}{x + y} = \frac{b x + a z}{x + z} = \frac{a y + b z}{y + z}

x + y + z \neq 0

\frac{a + b}{2}

\frac{y + z}{a} = \frac{z + x}{b} = \frac{x + y}{c}

\frac{x}{b + c - a} = \frac{y}{c + a - b} = \frac{z}{a + b - c}

\frac{3 x - 5 y}{5 z + 3 y} = \frac{x + 5 z}{y - 5 x} = \frac{y - z}{x - z}

\frac{x}{y}

x = 1 + a, y = - 3 - λ a, z = 1 + λ a

x = \frac{b}{2}, y = 1 + b, z = 2 - b

λ

s i n^{- 1} x + s i n^{- 1} y + s i n^{- 1} z = \frac{3 π}{2}

f (1) = 2, f (a + b) = f (a) f (b)

a, b, ϵ R

x^{f (1)} + y^{f (2)} + z^{f (3)} - \frac{x + y + z}{x^{f (1)} + y^{f (2)} + z^{f (3)}}

\frac{x}{y + z} = a; \frac{y}{z + x} = b; \frac{z}{x + y} = c;

\frac{1}{1 + a} + \frac{1}{1 + b} + \frac{1}{1 + c}

x = 2, y = 1

z = - 3

x^{3} + y^{3} + z^{3} - 3 x y z

Join BYJU'S Learning Program