Question

If $A=\left[\begin{array}{cc}1& 1\\ 1& 2\end{array}\right],B=\left[\begin{array}{cc}4& 1\\ 3& 1\end{array}\right],C=\left[\begin{array}{cc}24& 7\\ 31& 9\end{array}\right]$, then find matrix ${}^{\prime }{X}^{\prime }$ such that $AXB=C$.

• A. $\left[\begin{array}{cc}1& 1\\ 2& 3\end{array}\right]$
• B. $\left[\begin{array}{cc}2& 3\\ 1& 1\end{array}\right]$
• C. $\left[\begin{array}{cc}-2& 3\\ 1& -1\end{array}\right]$
• D. $\left[\begin{array}{cc}2& -3\\ 1& 1\end{array}\right]$

Answer 1

The correct option is B $\left[\begin{array}{cc}2& 3\\ 1& 1\end{array}\right]$