If A - - 1 2 -1- -1 1 2- 2 -1 1 - then det Adj Adj A is

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Adjoint of a Matrix

If A = [ 1 2 ...

Question

If A = $⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & - 1 - 1 & 1 & 2 2 & - 1 & 1 \end{matrix} ⎤ ⎥ ⎦$ , then det (Adj (Adj A)) is

(14)^{4}

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(14)^{6}

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(14)^{9}

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(14)^{2}

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⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & - 1 - 1 & 1 & 2 2 & - 1 & 1 \end{matrix} ⎤ ⎥ ⎦

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & - 1 - 1 & 1 & 2 2 & - 1 & 1 \end{matrix} ⎤ ⎥ ⎦

d e t [a d j (a d j (A))]

S_{1} :

3 * 3

{(d e t A)}^{2}

S_{2} :

3 * 3

a d j (2 A) = 8 | a d j A |

⎡ ⎢ ⎣ \begin{matrix} 2 & 1 & 1 1 & 2 & 1 1 & 1 & 2 \end{matrix} ⎤ ⎥ ⎦

A

3 \times 3

det (2 Adj(2 Adj(Adj(2A)))) = 2^{41},

det (A^{2})

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