If A=⎡⎢⎣−1−2−221−22−21⎤⎥⎦, Then adj(A) equals
A
A
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B
AT
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C
3A
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D
3AT
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Solution
The correct option is C3AT Given A=⎡⎢⎣−1−2−221−22−21⎤⎥⎦ AT=⎡⎢⎣−122−21−2−2−21⎤⎥⎦ Now, adjA=CT=⎡⎢⎣−3−6−663−66−63⎤⎥⎦T ⇒adjA=⎡⎢⎣−366−63−6−6−63⎤⎥⎦ ⇒adjA=3⎡⎢⎣−122−21−2−2−21⎤⎥⎦ ⇒adjA=3AT