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Byju's Answer
Standard XII
Mathematics
Inverse of a Matrix
If A = [ 1 ...
Question
If
A
=
[
1
−
2
3
−
4
2
5
]
and
B
=
⎡
⎢
⎣
2
3
4
5
2
1
⎤
⎥
⎦
. Find
A
B
and show that
A
B
â‰
B
A
A
A
B
=
[
0
−
4
10
−
3
]
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B
A
B
=
[
0
4
10
3
]
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C
A
B
=
[
0
−
4
10
3
]
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D
None of these.
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Solution
The correct option is
D
A
B
=
[
0
−
4
10
3
]
Given,
A
=
[
1
−
2
3
−
4
2
5
]
,
B
=
⎡
⎢
⎣
2
3
4
5
2
1
⎤
⎥
⎦
A
B
=
[
1
−
2
3
−
4
2
5
]
⎡
⎢
⎣
2
3
4
5
2
1
⎤
⎥
⎦
=
[
2
−
8
+
6
3
−
10
+
3
−
8
+
8
+
10
−
12
+
10
+
5
]
=
[
0
−
4
10
3
]
B
A
=
⎡
⎢
⎣
2
3
4
5
2
1
⎤
⎥
⎦
[
1
−
2
3
−
4
2
5
]
=
∣
∣ ∣
∣
2
−
12
−
4
+
6
6
+
15
4
−
20
−
8
+
10
12
+
25
2
−
4
−
4
+
2
−
6
+
5
∣
∣ ∣
∣
⎡
⎢
⎣
−
10
2
21
−
16
2
37
−
2
−
2
−
1
⎤
⎥
⎦
Hence
A
B
≠
B
A
Suggest Corrections
0
Similar questions
Q.
If
A
=
[
1
−
2
3
−
4
2
5
]
and
B
=
⎡
⎢
⎣
2
3
4
5
2
1
⎤
⎥
⎦
, then find
A
B
Q.
If
A
=
[
1
−
2
3
−
4
2
5
]
and
B
=
⎡
⎢
⎣
2
3
4
5
2
1
⎤
⎥
⎦
, then the product of AB and BA is
Q.
If
A
=
[
1
−
2
3
−
4
2
5
]
and
B
=
⎡
⎢
⎣
1
3
−
1
0
2
4
⎤
⎥
⎦
. Show that
(
A
B
)
′
=
?
Q.
If
A
=
[
1
−
2
3
−
4
2
5
]
and
B
=
⎡
⎢
⎣
1
3
−
1
0
2
4
⎤
⎥
⎦
, then show that
(
A
B
)
′
=
B
′
A
′
Q.
Let
A
=
[
1
−
2
3
3
2
−
1
]
and
B
=
⎡
⎢
⎣
2
3
−
1
2
4
−
5
⎤
⎥
⎦
. Find AB and BA and show that
A
B
≠
B
A
.
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