If A - begin bmatrix 111211311lendbmatrix then AA-A- 14B- beginbmatrix 1113 13 1lendbmatrix C- lbegin bmatrix 1 - 2 - 3 -2844-6 13 - 6 - 9 1lendbmatrix D- None of these

The correct option is C [ 1 amp; 2 amp;3; 2 amp;4 amp;6; 3 amp; 6 amp; 9; ]A' = [1 2 3] therefore AA' = = [ 1; 2; 3; ] [1 2 3] = [ ...

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Standard X

Mathematics

Transpose of a Matrix

If A =⟨ begin...

Question

If $A = ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦$ then AA' =

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⎡ ⎢ ⎣ \begin{matrix} 133 \end{matrix} ⎤ ⎥ ⎦

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⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 2 & 4 & 6 3 & 6 & 9 \end{matrix} ⎤ ⎥ ⎦

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Solution

The correct option is C $⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 2 & 4 & 6 3 & 6 & 9 \end{matrix} ⎤ ⎥ ⎦$
A' = [1 2 3] therefore AA' = $= ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦ [123] = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 2 & 4 & 6 3 & 6 & 9 \end{matrix} ⎤ ⎥ ⎦$

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Similar questions

Q. If

A = ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦

then AA' =

Q. If

A = ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦

then AA' =

If $A = [\begin{matrix} 5 & 4 3 & - 1 \end{matrix}], B = [\begin{matrix} 2 & 1 0 & 4 \end{matrix}]$ and $C = [\begin{matrix} - 3 & 2 1 & 0 \end{matrix}]$ then find A + B - C

Q. If

A = ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦

then AA' =

Which of the following are equal matrixes.

$A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 4 & 5 & 6 7 & 8 & 9 \end{matrix} ⎤ ⎥ ⎦$
$B = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 4 3 & 5 & 6 7 & 8 & 9 \end{matrix} ⎤ ⎥ ⎦$
$C = [\begin{matrix} 1 & 2 3 & 4 \end{matrix}]$
$D = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 4 & 5 & 6 7 & 8 & 9 \end{matrix} ⎤ ⎥ ⎦$
$E = [\begin{matrix} 1 & 3 2 & 4 \end{matrix}]$

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If A=⎡⎢⎣123⎤⎥⎦ then AA' =

The correct option is C ⎡⎢⎣123246369⎤⎥⎦A' = [1 2 3] therefore AA' = =⎡⎢⎣123⎤⎥⎦[123]=⎡⎢⎣123246369⎤⎥⎦

If $A = ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦$ then AA' =

The correct option is C $⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 2 & 4 & 6 3 & 6 & 9 \end{matrix} ⎤ ⎥ ⎦$
A' = [1 2 3] therefore AA' = $= ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦ [123] = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 2 & 4 & 6 3 & 6 & 9 \end{matrix} ⎤ ⎥ ⎦$