If A - begin bmatrix 111211311then AA -2 - 43 - 6 - 9 1lendbmatrix B- None of theseC- 14D-311311endbmatrix

The correct option is A [ 1 amp; 2 amp;3; 2 amp;4 amp;6; 3 amp; 6 amp; 9; ]A' = [1 2 3] therefore AA' = = [ 1; 2; 3; ] [1 2 3] = [ ...

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Byju's Answer

Standard XII

Mathematics

Transpose of a Matrix

If A = begin ...

Question

If $A = ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦$ then AA' =

14

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⎡ ⎢ ⎣ \begin{matrix} 133 \end{matrix} ⎤ ⎥ ⎦

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⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 2 & 4 & 6 3 & 6 & 9 \end{matrix} ⎤ ⎥ ⎦

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Solution

The correct option is C $⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 2 & 4 & 6 3 & 6 & 9 \end{matrix} ⎤ ⎥ ⎦$
A' = [1 2 3] therefore AA' = $= ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦ [123] = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 2 & 4 & 6 3 & 6 & 9 \end{matrix} ⎤ ⎥ ⎦$

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Similar questions

If $A = ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦$ then AA' =

Q. If

A = ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦

then AA' =

B + H C l \to A

If $A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 - 2 & 3 & - 1 3 & 1 & 2 \end{matrix} ⎤ ⎥ ⎦$ and I is a unit matrix of $3^{r d}$ order, then $(A^{2} + 9 I)$ equals

Q. If

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 - 2 & 3 & - 1 3 & 1 & 2 \end{matrix} ⎤ ⎥ ⎦

and I is a unit matrix of

3^{r d}

order, then

(A^{2} + 9 I)

equals

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If A=⎡⎢⎣123⎤⎥⎦ then AA' =

The correct option is C ⎡⎢⎣123246369⎤⎥⎦A' = [1 2 3] therefore AA' = =⎡⎢⎣123⎤⎥⎦[123]=⎡⎢⎣123246369⎤⎥⎦

If $A = ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦$ then AA' =

The correct option is C $⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 2 & 4 & 6 3 & 6 & 9 \end{matrix} ⎤ ⎥ ⎦$
A' = [1 2 3] therefore AA' = $= ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦ [123] = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 2 & 4 & 6 3 & 6 & 9 \end{matrix} ⎤ ⎥ ⎦$