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Question

If A=⎡⎢⎣12−3i3+4i2+3i04−5i3−4i4+5i2⎤⎥⎦ then A is

A
Hermitian
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B
Skew-Hermitian
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C
Symmetric
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D
Skew-Symmetric
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Solution

The correct option is C Hermitian
A=123i3+4i2+3i045i34i4+5i2
¯¯¯¯A=12+3i34i23i04+5i3+4i45i2
(¯¯¯¯A)T=123i3+4i2+3i045i34i4+5i2
So, (¯¯¯¯A)T=A
Hence, A is Hermitian

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