If A=⎡⎢⎣12−3i3+4i2+3i04−5i3−4i4+5i2⎤⎥⎦ then A is
A
Hermitian
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B
Skew-Hermitian
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C
Symmetric
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D
Skew-Symmetric
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Solution
The correct option is C Hermitian A=⎡⎢⎣12−3i3+4i2+3i04−5i3−4i4+5i2⎤⎥⎦ ¯¯¯¯A=⎡⎢⎣12+3i3−4i2−3i04+5i3+4i4−5i2⎤⎥⎦ ⇒(¯¯¯¯A)T=⎡⎢⎣12−3i3+4i2+3i04−5i3−4i4+5i2⎤⎥⎦ So, (¯¯¯¯A)T=A Hence, A is Hermitian