If A=[1−2],B=[22]and C=[−12], find 2A+B-5C
2A+B−5C=2[1−2]+[22]−5[−12]
=[2−4]+[22]−[−510]
=[2+2−(−5)−4+2−10]
=[9−12]
If 2160=2a.3b.5c, find a, b and c. Hence calculate the value of 3a×2−b×5−c
If 10800=2a × 3b × 5c then find the value of a, b and c.