If A=⎡⎢⎣−1−3−331−33−31⎤⎥⎦ then adj (A) is
A
=4⎡⎢⎣−233−32−3−332⎤⎥⎦
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B
=4⎡⎢⎣−23332−3−3−32⎤⎥⎦
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C
=4⎡⎢⎣−2−33−32−3−3−32⎤⎥⎦
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D
=4⎡⎢⎣−233−32−3−3−32⎤⎥⎦
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Solution
The correct option is D=4⎡⎢⎣−233−32−3−3−32⎤⎥⎦ Given A=⎡⎢⎣−1−3−331−33−31⎤⎥⎦ C=⎡⎢⎣−8−12−12128−1212−128⎤⎥⎦ adjA=CT=⎡⎢⎣−81212−128−12−12−128⎤⎥⎦ =4⎡⎢⎣−233−32−3−3−32⎤⎥⎦