If A - bmatrix 2 - 0 - 1111 - 1 - 0 12 - 1 - 1 1lend bmatrix and adj A- begin bmatrix 1 - 2 -1x - y - z -1 -2 - 2 lendbmatrix then x - y - z A- -1-0-1B- -1-0-1C- 1-0-1D- -1-1-1

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Byju's Answer

Standard XII

Mathematics

Consistency of Linear System of Equations

If A = bmatri...

Question

If $A = ⎡ ⎢ ⎣ \begin{matrix} 2 & 0 & 1 1 & 1 & 0 2 & 1 & 1 \end{matrix} ⎤ ⎥ ⎦$ and $a d j A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & - 1 x & y & z - 1 & - 2 & 2 \end{matrix} ⎤ ⎥ ⎦$ then $(x, y, z)$

(-1,0,-1)

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(-1,0,1)

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(1,0,-1)

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(-1,-1,1)

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Solution

The correct option is B
(-1,0,1)

x, y, z are the cofactors of the elements of $C_{2} \Rightarrow (x, y, z) = (- 1, 0, 1)$

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Similar questions

Q. If

⎡ ⎢ ⎣ \begin{matrix} 1 & 1 & 1 1 & - 2 & - 2 1 & 3 & 1 \end{matrix} ⎤ ⎥ ⎦

⎡ ⎢ ⎣ \begin{matrix} x y z \end{matrix} ⎤ ⎥ ⎦ = ⎡ ⎢ ⎣ \begin{matrix} 034 \end{matrix} ⎤ ⎥ ⎦

, then

⎡ ⎢ ⎣ \begin{matrix} x y z \end{matrix} ⎤ ⎥ ⎦

is equal to.

Q. If

⎡ ⎢ ⎣ \begin{matrix} 1 & 0 & 0 0 & 0 & 1 0 & 1 & 0 \end{matrix} ⎤ ⎥ ⎦ ⎡ ⎢ ⎣ \begin{matrix} x y z \end{matrix} ⎤ ⎥ ⎦ = ⎡ ⎢ ⎣ \begin{matrix} 2 - 1 3 \end{matrix} ⎤ ⎥ ⎦

, find

x, y, z

Q. If

[\begin{matrix} x - y & 1 & z 2 x - y & 0 & w \end{matrix}] = [\begin{matrix} - 1 & 1 & 2 0 & 0 & 5 \end{matrix}]

,then find

x + y + z + w

Solve the equation of x,y, z and t, if $2 [\begin{matrix} x & z y & t \end{matrix}] + 3 [\begin{matrix} 1 & - 1 0 & 2 \end{matrix}] = 3 [\begin{matrix} 3 & 5 4 & 6 \end{matrix}]$

Q. If

⎡ ⎢ ⎣ \begin{matrix} 3 & 2 & - 1 4 & 9 & 2 5 & 0 & - 2 \end{matrix} ⎤ ⎥ ⎦ ⎡ ⎢ ⎣ \begin{matrix} x y z \end{matrix} ⎤ ⎥ ⎦ = ⎡ ⎢ ⎣ \begin{matrix} 072 \end{matrix} ⎤ ⎥ ⎦

, then

(x, y, z) =

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IfA=⎡⎢⎣201110211⎤⎥⎦ and adjA=⎡⎢⎣12−1xyz−1−22⎤⎥⎦ then (x,y,z)

The correct option is B (-1,0,1) x, y, z are the cofactors of the elements of C2⇒(x,y,z)=(−1,0,1)

If $A = ⎡ ⎢ ⎣ \begin{matrix} 2 & 0 & 1 1 & 1 & 0 2 & 1 & 1 \end{matrix} ⎤ ⎥ ⎦$ and $a d j A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & - 1 x & y & z - 1 & - 2 & 2 \end{matrix} ⎤ ⎥ ⎦$ then $(x, y, z)$

The correct option is B
(-1,0,1)

x, y, z are the cofactors of the elements of $C_{2} \Rightarrow (x, y, z) = (- 1, 0, 1)$