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Question

If A=[2113], evaluating A23A+21 where I is a unit matrix of order 2.(4).

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Solution

A2=A.A=[2113][2113][41232+31+9]=[3558]3A3[2113][6339]2I=2[1001][2002]puttingallthevalueinabove,weget[3558][6302]+[2002][3221]+[2002][1221]Ans.

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