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Question

If A=[2−131] and B=[1472], 3A−2B is

A
[41151]
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B
[51151]
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C
[41153]
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D
None of these
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Solution

The correct option is A [41151]
The value of 3A2B=3[2131]2[1472]
=[6393][28144]
=[623891434]
=[41151]
Hence, option A.

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