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Question

If A=[2−131] and B=[1472], then the value 3A−2B is

A
[31141]
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B
[4151]
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C
[41151]
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D
[41131]
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Solution

The correct option is C [41151]
3A2B=3[2131]2[1472]

=[6393][28144]

=[623891434]

=[41151]

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