If A- 2 2- -3 2 -B- 0 -1- 1 0 - - then B -1 A -1 -1 -

The correct option is A [ 2 2; 2 3 ] Now , (AB) ^ 1 = B ^ 1 A ^ 1 #160;So, ( B ^ 1 A ^ 1 )^ 1 =(A^ 1 )^ 1 (B^ 1 )^ 1 #160; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Statement

If A=[ 2 2;...

Question

If $A = [\begin{matrix} 2 & 2 - 3 & 2 \end{matrix}], B = [\begin{matrix} 0 & - 1 1 & 0 \end{matrix}]$ , then ${(B^{- 1} A^{- 1})}^{- 1} =$ ...........

[\begin{matrix} 2 & - 2 2 & 3 \end{matrix}]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[\begin{matrix} 2 & 2 - 2 & 3 \end{matrix}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[\begin{matrix} 2 & - 3 2 & 2 \end{matrix}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[\begin{matrix} 1 & - 1 - 2 & 3 \end{matrix}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

A = [\begin{matrix} 2 & 2 - 3 & 2 \end{matrix}], B = [\begin{matrix} 0 & - 1 1 & 0 \end{matrix}],

(B^{- 1} A^{- 1})^{- 1} =

A = [\begin{matrix} 2 & 2 - 3 & 2 \end{matrix}], B = [\begin{matrix} 0 & - 1 1 & 0 \end{matrix}]

B^{- 1} A^{- 1}

A = [\begin{matrix} 2 & 2 - 3 & 2 \end{matrix}]

B = [\begin{matrix} 0 & - 1 1 & 0 \end{matrix}],

(B^{- 1} A^{- 1})^{- 1}

t_{r} = \frac{1^{2} + 2^{2} + 3^{2} + . . . + r^{2}}{1^{3} + 2^{3} + . . . + r^{3}}

S_{n} = n \sum r = 1 {(- 1)}^{r} . t_{r},

lim n \to \infty S_{n} = \frac{2}{3}

1^{2} + 2^{2} + 3^{2} + . . . + r^{2} = \frac{r (r + 1) (2 r + 1)}{6}

1^{3} + 2^{3} + 3^{3} + . . . + r^{3} = {(\frac{r (r + 1)}{2})}^{2}

1 + \frac{1 + 2}{2!} + \frac{1 + 2 + 2^{2}}{3!} + \frac{1 + 2 + 2^{2} + 2^{3}}{4!} \dots . =

Join BYJU'S Learning Program