If A - begin bmatrix 38111-1 - 211endbmatrix - then A 2-5 A is equal toA- IB- - IC- 7 ID- -7 I

The correct option is D 7I nbsp; nbsp; nbsp;A^2=[ 3 amp;1; 1 amp;2; ][ 3 amp;1; 1 amp;2; ]=[ 8 amp;5; 5 amp;3; ...

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Scalar Multiplication of a Matrix

If A = begin ...

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If $A = [\begin{matrix} 3 & 1 - 1 & 2 \end{matrix}],$ then $A^{2} - 5 A$ is equal to

I

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- I

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7 I

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- 7 I

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If $A = [\begin{matrix} 3 & 1 - 1 & 2 \end{matrix}]$ , show that $A^{2} - 5 A + 7 I = 0$ . Hence, find $A^{- 1}$

A = [\begin{matrix} 5 a & - b 3 & 2 \end{matrix}]

A = A A^{T}

A = [\begin{matrix} 5 a & - b 3 & 2 \end{matrix}]

A = A A^{T}

A = [\begin{matrix} 3 & 1 - 1 & 2 \end{matrix}]

I = [\begin{matrix} 1 & 0 0 & 1 \end{matrix}]

A^{2} - 5 A + 7 I

I f b + i c = (1 + a) z a n d a^{2} + b^{2} + c^{2} = 1, t h e n \frac{1 + i z}{1 - i z} i s e q u a l t o

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