If A- 4 1 0- 1 -2 2 -B- 2 0 -1- 3 1 4 -C- 1- 2- -1 - and 3B-2AC-2X-0 then X-

The correct option is B 1 2 [ 3; 13 ] X= 1/2(3B 2A)C = 12[ 2 amp; 2 amp; 3; 7 amp;7 amp;8 ][ 1; 2; 1 ]= 12[ 3; 13 ]=12[ 3; ...

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Addition and Subtraction of a Matrix

If A=[ 4 1 ...

Question

If $A = [\begin{matrix} 4 & 1 & 0 1 & - 2 & 2 \end{matrix}], B = [\begin{matrix} 2 & 0 & - 1 3 & 1 & 4 \end{matrix}], C = ⎡ ⎢ ⎣ \begin{matrix} 12 - 1 \end{matrix} ⎤ ⎥ ⎦$ and $(3 B - 2 A) C + 2 X = 0$ then $X =$

\frac{1}{2} [\begin{matrix} 313 \end{matrix}]

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\frac{1}{2} [\begin{matrix} 3 - 13 \end{matrix}]

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\frac{1}{2} [\begin{matrix} - 3 13 \end{matrix}]

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[\begin{matrix} 3 - 13 \end{matrix}]

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Solution

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Similar questions

A = [\begin{matrix} 410 1 - 22 \end{matrix}],

B = [\begin{matrix} 20 - 1 314 \end{matrix}],

C = ⎡ ⎢ ⎣ \begin{matrix} 12 - 1 \end{matrix} ⎤ ⎥ ⎦

(3 B - 2 A) C + 2 X = 0,

X

1 f A = [\begin{matrix} 4 & 1 & 0 1 & - 2 & 2 \end{matrix}], B = [\begin{matrix} 2 & 0 & - 1 3 & 1 & 4 \end{matrix}]

C = ⎡ ⎢ ⎣ \begin{matrix} 12 - 1 \end{matrix} ⎤ ⎥ ⎦

(3 B - 2 A) C + 2 X = 0

X

x^{2} + 2 x + 3 = 0

a x^{2} + b x + c = 0

ϵ

Evaluate the determinants..

$∣ ∣ ∣ ∣ \begin{matrix} 3 & - 1 & - 2 0 & 0 & - 1 3 & - 5 & 0 \end{matrix} ∣ ∣ ∣ ∣$

$∣ ∣ ∣ ∣ \begin{matrix} 3 & - 4 & 5 1 & 1 & - 2 2 & 3 & 1 \end{matrix} ∣ ∣ ∣ ∣$

$∣ ∣ ∣ ∣ \begin{matrix} 0 & 1 & 2 - 1 & 0 & - 3 - 2 & 3 & 0 \end{matrix} ∣ ∣ ∣ ∣$

$∣ ∣ ∣ ∣ \begin{matrix} 2 & - 1 & - 2 0 & 2 & - 1 3 & - 5 & 0 \end{matrix} ∣ ∣ ∣ ∣$

I = \int s i n^{- 1} (\frac{2 x + 2}{\sqrt{4 x^{2} + 8 x + 13}}) d x = (x + 1) t a n^{- 1} \frac{2 x + 2}{3} - \frac{A}{248} log (4 x^{2} + 8 x + 13) + C

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