If A - begin bmatrix 4 - 3 - 6 -81 -3 -6 - 2lendbmatrix Find a matrix C such that C - A -2 BA- beginbmatrix 2 -9 -18 - 12lendbmatrix B- Vbeginbmatrix 2 - 9 - 18 -12lend bmatrix 3 - 8 -12 - 6endbmatrix D- 3 -8 - 12 -6 e n d b m a t r i x

The correct option is B [ 2 amp; 9 amp; 18 amp; 12 ] C=A 2B A 2B=[ 4 amp; 3 amp; 6 amp; 8 ] 2[ 1 amp; 3 amp; 6 amp;2 ] =[ 4 ...

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Row Matrix

If A = begin ...

Question

If $A = [\begin{matrix} 4 & 3 & 6 & - 8 \end{matrix}], B = [\begin{matrix} 1 & - 3 & - 6 & 2 \end{matrix}]$
Find a matrix C such that C=A-2B

$[\begin{matrix} 2 & 9 & 18 & - 12 \end{matrix}]$

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$[\begin{matrix} 2 & - 9 & - 18 & 12 \end{matrix}]$

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$[\begin{matrix} 3 & 8 & - 12 & 6 \end{matrix}]$

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$[\begin{matrix} 3 & - 8 & 12 & - 6 \end{matrix}]$

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Solution

The correct option is A
$[\begin{matrix} 2 & 9 & 18 & - 12 \end{matrix}]$

$C = A - 2 B$
$A - 2 B$ $= [\begin{matrix} 4 & 3 & 6 & - 8 \end{matrix}] - 2 [\begin{matrix} 1 & - 3 & - 6 & 2 \end{matrix}] = [\begin{matrix} 4 & 3 & 6 & - 8 \end{matrix}] - [\begin{matrix} 2 & - 6 & - 12 & 4 \end{matrix}] = [\begin{matrix} 2 & 9 & 18 & - 12 \end{matrix}]$

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If A=[436−8],B=[1−3−62] Find a matrix C such that C=A-2B

The correct option is A [2918−12] C=A−2B A−2B=[436−8]−2[1−3−62]=[436−8]−[2−6−124]=[2918−12]

If $A = [\begin{matrix} 4 & 3 & 6 & - 8 \end{matrix}], B = [\begin{matrix} 1 & - 3 & - 6 & 2 \end{matrix}]$
Find a matrix C such that C=A-2B