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Question

If A=[5109122] , then det (A100−5A99) is

A
5
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B
1
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C
109
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D
108
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Solution

The correct option is B 109
Given : A=[5109122]
Calculating determinant

|A|=110109=1
A1005A99=A99(A5I)
A1005A99=|A|99|A5I|
=1.0109117
=1.(109)
=109

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