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B
2A−3I
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C
−2A−3I
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D
−2A+3I
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Solution
The correct option is C−2A−3I The characteristics equation for A is : |A−λI|=0 ⇒∣∣∣5−λ3−21−λ∣∣∣=0⇒(5−λ)(1−λ)+6=0⇒λ2−6λ+11=0
From Cayley-Hamilton formula : matrix A will satisfy the characteristics equation, ⇒A2−6A+11I=O⇒3A2−18A+33I=O⇒3A2−20A+30I=−3I−2A