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Question

If A=622231213, then |xIA| equals

A
x3+12x236x+12
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B
x312x2+36x12
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C
x312x236x+12
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D
none of these
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Solution

The correct option is B none of these
A=622231213
|xIA|=x6222x+3121x3
applying R3R2+R3 and expanding gives
|xIA|=x6222x+310x+4x2
=x36x210x+36
Hence, option D is correct.

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