If A - begin bmatrix -885112 - 4lendbmatrix satisfies the equation x 2-4 x - p -0- then p -A- 42B- 36C- 24D- 64

The correct option is A 42 Characteristic equation is x^2+4x 42=0⇒ p=42 ...

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Condition for a Conic to Be a Pair of Straight Lines

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If $A = [\begin{matrix} - 8 & 5 2 & 4 \end{matrix}]$ satisfies the equation $x^{2} + 4 x - p = 0, t h e n p =$

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If $A = [\begin{matrix} - 8 & 5 2 & 4 \end{matrix}]$ satisfies the equation $x^{2} + 4 x - p = 0, t h e n p =$

A = [\begin{matrix} a & b c & d \end{matrix}]

b c \neq 0)^{10}

x^{2} + k = 0

p, q, r

3

[\begin{matrix} p & q & r \end{matrix}] ⎡ ⎢ ⎣ \begin{matrix} 3 & 4 & 1 3 & 2 & 3 2 & 0 & 2 \end{matrix} ⎤ ⎥ ⎦ = [\begin{matrix} 3 & 0 & 1 \end{matrix}]

2 p + q - r

[\begin{matrix} a & b c & d \end{matrix}]

λ^{2} + k = 0

X = [\begin{matrix} 3 & 1 - 4 & - 1 \end{matrix}], B = [\begin{matrix} 5 & 2 - 2 & 1 \end{matrix}]

A = [\begin{matrix} p & q r & s \end{matrix}]

A X = B

A

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