If A- a 2 ab ac- ab b 2 bc- ac bc c 2 - and a2-b2-c2-1 then A2-

The correct option is A A A^2[ a^2 amp;ab amp;ac; ab amp;b^2 amp;bc; ac amp;bc amp;c^2 ][ a^2 amp;ab amp;ac; ab amp;b^2 ...

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If A=[ a 2 ...

Question

If $A = ⎡ ⎢ ⎣ \begin{matrix} a^{2} & a b & a c a b & b^{2} & b c a c & b c & c^{2} \end{matrix} ⎤ ⎥ ⎦$ and $a^{2} + b^{2} + c^{2} = 1$ then $A^{2} =$

2 A

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A

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3 A

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\frac{1}{2} A

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A = ⎡ ⎢ ⎣ \begin{matrix} a^{2} & a b & a c a b & b^{2} & b c a c & b c & c^{2} \end{matrix} ⎤ ⎥ ⎦

a^{2} + b^{2} + c^{2} = 1

A^{2} =

A = ⎡ ⎢ ⎣ \begin{matrix} a^{2} & a b & a c a b & b^{2} & b c a c & b c & c^{2} \end{matrix} ⎤ ⎥ ⎦

a^{2} + b^{2} + c^{2} = 1,

A^{2} =

A = ⎡ ⎢ ⎣ \begin{matrix} 0 & c & - b - c & 0 & a b & - a & 0 \end{matrix} ⎤ ⎥ ⎦

B = ⎡ ⎢ ⎣ \begin{matrix} a^{2} & a b & a c a b & b^{2} & b c a c & b c & c^{2} \end{matrix} ⎤ ⎥ ⎦,

A B =

a^{2}, b^{2}, c^{2}

a^{2} a n d c^{2}

a > 0

a^{2} + b^{2} = 13

a b = 6

3 {(a + b)}^{2} - 2 {(a - b)}^{2}

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