If A=[abba] and A2=[αββα], then
α=a2+b2,β=ab
α=a2+b2,β=2ab
α=a2+b2,β=a2−b2
α=2ab,β=a2+b2
A2=[αββα]=[abba][abba];α=α2+b2;β=2ab
If A is a square matrix of order 2 such that A2=0, then