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Question

If A=[abcd], then A−1 = [MP PET 1988]


A

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B

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C

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D

None of these

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Solution

The correct option is A


A−1 = adjA|A|

But, |A| =[abcd] = ab - cd and adj A =[b−c−da]

Therefore, A−1 = 1ab−cd [b−c−da]


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