If A = [α011] , B = [1051] whenever A2=B then values of α is
A
1
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B
−1
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C
4
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D
no real value of α
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Solution
The correct option is D no real value of α A2 = B⇒[α011][α011]=[1051] ⇒[α20α+11]=[1051] ⇒α2 = 1, α + 1 = 5 ∴α=±1,α=4 There is no real value of α which satisfies both.