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Question

If A=[cosxsinx−sinxcosx] and A adj A=k[1001] then the value of k is

A
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B
1
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C
2
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D
3
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Solution

The correct option is A 1
We know that,
A(adj A)=|A|I
Given, A=[cosxsinxsinxcosx]
|A|=cos2x+sin2x=1
|A|=cos2x+sin2x=1
A(adjA)=1I=kI
k=1.

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