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Question

If A=[i00−i],B=[0−110],C=[0ii0], then A2+B2+C2=

A
2I
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B
2I
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C
3I
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D
3I
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Solution

The correct option is D 3I
A=[i00i],B=[0110],C=[0ii0]
A2+B2+C2
=[i00i][i00i]+[0110][0110]+[0ii0][0ii0]
=[1001]+[1001]+[1001]
=[3003]=3I

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