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Question
If A=⎡⎢⎣x32−3y−7−270⎤⎥⎦ and A=−A′, then x+y is equal to
If A=⎡⎢⎣x32−3y−7−270⎤⎥⎦ and A=−A′, then x+y is equal to
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Solution
The correct option is C 0
A=−A1⇒⎡⎢⎣x32−3y−7−270⎤⎥⎦−⎡⎢⎣x−3−23y72−70⎤⎥⎦⇒⎡⎢⎣x32−2y−7−270⎤⎥⎦=⎡⎢⎣−x32−3−y−7−270⎤⎥⎦x=−xy=−y⇒x=0y=0x+y=0
A=−A1⇒⎡⎢⎣x32−3y−7−270⎤⎥⎦−⎡⎢⎣x−3−23y72−70⎤⎥⎦⇒⎡⎢⎣x32−2y−7−270⎤⎥⎦=⎡⎢⎣−x32−3−y−7−270⎤⎥⎦x=−xy=−y⇒x=0y=0x+y=0
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