Question

If $A=\left[\begin{array}{ccc}x& y& z\end{array}\right],$ $B=\left[\begin{array}{ccc}a& h& g\\ h& b& f\\ g& f& c\end{array}\right],C={\left[\begin{array}{ccc}\alpha & \beta & \gamma \end{array}\right]}^T$ then $ABC$ is

Answer 1

$A=\left[\begin{array}{ccc}x& y& z\end{array}\right]B=\left[\begin{array}{ccc}a& h& g\\ h& b& f\\ g& f& c\end{array}\right],C=\left[\begin{array}{c}\alpha \\ \beta \\ \gamma \end{array}\right]1\times 33\times 33\times 1$

$\Rightarrow ABC$ is $1\times 1$ matrix.