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Question

If a,β,1 are the roots of x32x25x+6=0 then 3a+β=_______ifa>0

A
7
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B
5
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C
14
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D
10
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Solution

The correct option is A 7
f(x)=x32x25x+6(x1)
is a root of f(x)
f(x)=(x1)(x23x6)=(x1)(x3)(x+2)a=3,β=23a+β=92=7

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