wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If a,β,1 are the roots of x32x25x+6=0 then 3a+β=_______ifa>0

A
7
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
14
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 7
f(x)=x32x25x+6(x1)
is a root of f(x)
f(x)=(x1)(x23x6)=(x1)(x3)(x+2)a=3,β=23a+β=92=7

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon