If a body is thrown up with an initial velocity u and covers a height of h, then $h = \frac{u^{2}}{2 g}$ .

False

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True

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Solution

The correct option is B True

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If a body is thrown up with an initial velocity $u$ and covers a maximum height of $h$ , then $h$ is equal to $\frac{u^{2}}{2 g}$ :

If a body is thrown up with an initial velocity $u$ and covers a maximum height of $h$ , then $h$ is equal to $\frac{u^{2}}{2 g}$ . [ $g$ is the acceleration due to gravity]

If a body is thrown up with an initial velocity $u$ and covers a maximum height of $h$ , then $h$ is equal to

Q. If a body is thrown up with an initial velocity u and covers a maximum height of h, then h is equal to

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If a body is thrown up with an initial velocity u and covers a height of h, then h=u22g.

The correct option is B True

If a body is thrown up with an initial velocity u and covers a height of h, then $h = \frac{u^{2}}{2 g}$ .