If a body of mass $0.98 k g$ is made to oscillate on a spring of force constant $4.84 N / m$ , the angular frequency of the body is

1.22 r a d / s e c

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2.22 r a d / s e c

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3.22 r a d / s e c

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4.22 r a d / s e c

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Solution

The correct option is C $2.22 r a d / s e c$
Given:
The mass of the body is $m = 0.98 k g$ .
The spring constant of the spring is $k = 4.84 N / m$ .

The angular frequency of the system is given by:
$ω = \sqrt{k / m}$

$= \sqrt{\frac{4.84}{0.98}}$

$= 2.22 r a d / s e c$

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If a body of mass 0.98 kg is made to oscillate on a spring of force constant 4.84 N/m, the angular frequency of the body is

The correct option is C 2.22 rad/secGiven:The mass of the body is m=0.98 kg.The spring constant of the spring is k=4.84 N/m.The angular frequency of the system is given by:ω=√k/m=√4.840.98=2.22 rad/sec

If a body of mass $0.98 k g$ is made to oscillate on a spring of force constant $4.84 N / m$ , the angular frequency of the body is

The correct option is C $2.22 r a d / s e c$
Given:
The mass of the body is $m = 0.98 k g$ .
The spring constant of the spring is $k = 4.84 N / m$ .

The angular frequency of the system is given by:
$ω = \sqrt{k / m}$

$= \sqrt{\frac{4.84}{0.98}}$

$= 2.22 r a d / s e c$