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Question

If a body of mass200gfalls from a height of 200m and its total P.E. is converted into K.E. at the point of contact of the body with the earth's surface, then what is the decrease in P.E. of the body at the contact (g=10m/s2).


A

200J

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B

400J

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C

600J

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D

900J

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Solution

The correct option is B

400J


Step 1: Given data:

The body of mass m=200g

The height h=200m

The acceleration due to gravity g=10m/s2

Step 2: Formula used:

Initial potential energy P.E.=m×g×h

Therefore,

P.E.=0.200kg×10m/s2×200mP.E.=400J

Therefore, the decrease in P.E. of the body at the contact 400J.

Hence, the correct option is (B).


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