If a body projected up with a velocity $u$ rises to a height $h$ , a body of double the mass projected with a double the velocity rises to a height of:

8 h

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4 h

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2 h

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h

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Solution

The correct option is B $4 h$
$h \propto u^{2}$ , for a body projected vertically upwards.
So, maximum height, $h$ is independent of mass.
So, $\frac{h_{2}}{h_{1}} = (\frac{u_{2}}{u_{1}})^{2}$
$\Rightarrow h_{2} = h (\frac{2 u}{u})^{2} = 4 h$

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If a body projected up with a velocity u rises to a height h, a body of double the mass projected with a double the velocity rises to a height of:

The correct option is B 4hh∝u2, for a body projected vertically upwards.So, maximum height, h is independent of mass.So, h2h1=(u2u1)2⇒h2=h(2uu)2=4h

If a body projected up with a velocity $u$ rises to a height $h$ , a body of double the mass projected with a double the velocity rises to a height of:

The correct option is B $4 h$
$h \propto u^{2}$ , for a body projected vertically upwards.
So, maximum height, $h$ is independent of mass.
So, $\frac{h_{2}}{h_{1}} = (\frac{u_{2}}{u_{1}})^{2}$
$\Rightarrow h_{2} = h (\frac{2 u}{u})^{2} = 4 h$