Question

If a body starts from rest and travels $120\text{cm}$ in the $6^{th}$ second, then the acceleration of the body is

• A. $0.2m/s^2$
• B. $0.027m/s^2$
• C. $0.218m/s^2$
• D. $0.03m/s^2$

Answer 1

The correct option is C $0.218m/s^2$

Given, $u=0,S_{6^{th}}=120\text{cm}=1.2\text{m}$
As we know that,
$S_n=u+\frac{a}{2}(2n-1)$
$\Rightarrow 1.2=0+\frac{a}{2}(2\times 6-1)$
$\Rightarrow a=\frac{1.2\times 2}{11}=0.218m/s^2$