If a bottle weighs 30 g when filled with a liquid and 48 g when filled with water, how to calculate the density of liquid if density of water at 4 degrees is $1000 k g / m^{3}$

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Solution

mass of bottle =30g
mass of liquid =53.3-30 =23.3g
mass of water =48-30=18g=0.01kg
first calculate volume
density =mass/volume
we know mass of water, density of water
volume =mass/density = $\frac{0.018}{1000} = 18 \times 10^{- 6} m^{3}$
now we find the density of liquid
density $\frac{23.3 \times 10^{- 3}}{18 \times 10^{- 6}} = 1294.4 k g / m^{3}$

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If a bottle weighs 30 g when filled with a liquid and 48 g when filled with water, how to calculate the density of liquid if density of water at 4 degrees is 1000kg/m3

mass of bottle =30g mass of liquid =53.3-30 =23.3g mass of water =48-30=18g=0.01kg first calculate volume density =mass/volume we know mass of water, density of water volume =mass/density =0.0181000=18×10−6m3 now we find the density of liquid density 23.3×10−318×10−6=1294.4kg/m3

If a bottle weighs 30 g when filled with a liquid and 48 g when filled with water, how to calculate the density of liquid if density of water at 4 degrees is $1000 k g / m^{3}$