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Bosch Method

If a bunch of...

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If a bunch of atoms consists of hydrogen atoms, in their first excited state, He+ ions in the 3rd excited state and Li2+ ions in 5th excited state. What is max. no of spectral lines in the bunch.

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Solution

$A l l t h e a t o m s a r e 1 e l e c t r o n s p e c i e s . F i r s t e x c i t e d s t a t e m e a n s n = 2 N o o f s p e c t r a l l i n e s = \frac{n (n - 1)}{2} = \frac{2 (2 - 1)}{2} = 1 T h i r d e x c i t e d s t a t e m e a n s n = 4 N o o f s p e c t r a l l i n e s = \frac{n (n - 1)}{2} = \frac{4 (4 - 1)}{2} = 6 F i f t h e x c i t e d s t a t e m e a n s n = 6 N o o f s p e c t r a l l i n e s = \frac{n (n - 1)}{2} = \frac{6 (6 - 1)}{2} = 15 S o t h e t o t a l s p e c t r a l l i n e s = 1 + 6 + 15 = 22$

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