Question

$Ifa=c,\text{show that}cba-abc=0.$

Answer 1

$\text{Given:}a=c\text{To show :}cba-abc=0Proof:cba=100c+10b+a...\left(i\right)\text{(By using property 3)}abc=100a+10b+c...\left(ii\right)\text{(By using property 3)}Since,a=c,\therefore \text{Substitute the valur of}a=c\text{in equation (i) and (ii), we get}cba=100c+10b+c...\left(iii\right)abc=100c+10b+c...\left(iv\right)\text{Subtracting (iv) from (iii), we get}cba-abc=100c+10b+c-100c-10b-c\Rightarrow cba-abc=0\Rightarrow cba=abc\text{Hence proved.}$