wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If a capacitor of 8 μF is connected to a 220 V. 100 Hz ac source and the current passing through it is 65 mA, then the rms voltage across it is

A
129.4 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
12.94 V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1.294V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
15V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 12.94 V
Irms=65mA=0.065A
C=8μF=8×106F,ν=100Hz

Capacitive reactance,
XC=12πνC
=12×3.14×100×8×106=199 Ω

Then RMS voltage across the capacitor is:

Vrms=IrmsXC
=0.065×199

12.94V

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Dimensional Analysis
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon