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Question

If a capacitor of 8 μF is connected to a 220 V. 100 Hz ac source and the current passing through it is 65 mA, then the rms voltage across it is

A
129.4 V
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B
12.94 V
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C
1.294V
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D
15V
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Solution

The correct option is B 12.94 V
Irms=65mA=0.065A
C=8μF=8×106F,ν=100Hz

Capacitive reactance,
XC=12πνC
=12×3.14×100×8×106=199 Ω

Then RMS voltage across the capacitor is:

Vrms=IrmsXC
=0.065×199

12.94V

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