If a car at rest accelerated uniformly to a speed of $144 k m / h o u r$ in $20 s e c o n d$ it covers a distance:

Question

Q. If a car at rest is accelerated uniformly to the speed of

144 km/h

in

20 s

, distance covered by the car in

20 s

is

Answer 1

$u = 0, v = 144 k m / h o u r = 144 \times \frac{5}{18} m / s e c = 40 m / s e c$

$v = u + a t$

$\Rightarrow a = \frac{v - u}{t} = \frac{40 - 0}{20} = 2 m / {s e c}^{2}$

$∴ s = u t + \frac{1}{2} a t^{2}$

$= \frac{1}{2} \times 2 \times {(20)}^{2} = 400 m$

If a car at rest accelerated uniformly to a speed of 144km/hour in 20second it covers a distance: