If a car covered $200 k m$ in $2 h o u r s$ and a motorcycle covered $120 k m$ in the same time, then
$[D i s \tan c e c o v e r e d b y t h e m o t o r c y c l e] : [D i s \tan c e c o v e r e d b y t h e c a r] =$

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Solution

Distance covered by car in $2 h o u r s = 200 k m$
Distance covered by motorcycle in same time $= 120 k m$
$[D i s \tan c e c o v e r e d b y t h e m o t o r c y c l e] : [D i s \tan c e c o v e r e d b y t h e c a r] =$ $120 : 200$
Lowest form of $120 : 200$ $= \frac{120}{200} = \frac{3}{5} = 3 : 5$ (Divide both $120$ and $200$ by their HCF $40$ )
Hence, $[D i s \tan c e c o v e r e d b y t h e m o t o r c y c l e] : [D i s \tan c e c o v e r e d b y t h e c a r] =$ $3 : 5$

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