If a car moves with velocity 'u' and its maximum retardation is 'a', its minimum stopping distance is proportional to
a)u
b)u2
c)u3
d)u1/2
The correct answer is option B
As we know, by using 3rd equation of motion we can say,
v²=u²+2as
As the body retards, resulting the body to stop final once its energy drains out. v=0
0=u2+2(−a)(s)
s=u22a
sαu2
∴\therefore ∴ s is proportional to u²